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electron has an initial speed of 6.35 x 10 m/s in a uniform 4.66 x 10% N/C strength electric fneld. The field accelerates the electron in the direction opposite to ts initial velocity (o) What is the direction of the electric field? O opposite direction to the electrons initial velocity O same direction as the electrons initial velocity O not enough information to decide (b) How far does the electron travel before coming to rest? (e) How long does it take the electron to come to rest? (d) What is the electrons speed when it returns to its starting pointi? m/s Addtional Materials Reading My Notes
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Solution Fvon gven dda field : = 4.66x105 NIC. C an Ca) Ke divecion of -the elechic field Electic ield acCuralex ino(イbsit direchon of field * Fİdric field accurata -the regtively changed elechon ») so, I is in the Same diredion as dechor indiab velociy ore Comin E. then6 -35 x1o c) Ho o ak th elechon o Come to ver 6.35 x 10 3.134 XU Thi elecvic oe Consoli s

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