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(1) An electron has an initial speed of 7.10 106 m/s in a uniform 5.42 105...

(1) An electron has an initial speed of 7.10 106 m/s in a uniform 5.42 105 N/C strength electric field. The field accelerates the electron in the direction opposite to its initial velocity.

(a) What is the direction of the electric field? opposite direction to the electron's initial velocity same direction as the electron's initial velocity not enough information to decide

(b) How far does the electron travel before coming to rest?

(c) How long does it take the electron to come to rest?

(d) What is the electron's speed when it returns to its starting point?

(2) (a) What magnitude point charge creates a 70,000 N/C electric field at a distance of 0.226 m?

(b) How large is the field at 21.2 m?

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Answer #1

301. Givens 7. 10x10 mig 5.42X10 M/C Dizertion of electric field = Same direction of the electrons initial velocity e E b a

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