Answer)
We have a two tailed test
For which p-value is = 0.068
A)
This is a one tailed test so p-value is = 0.068/2 = 0.034
B)
This is also one tailed test
But sample x = -11.2
That is p-value would be 1 - 0.034 = 0.966
suppose you test null hypothesis Ho : μι_Ha versus Ha : μ.μ2 , software gives 12.3 degrees of freedom for your t test. Answer the following questions: a) If test statistics t-2.25 5, use the rejection region to decide if Ho be rejected or not at a .0.05? Include a sketch, clearly label critical value(s) and rejection and nonrejection regions. b) If test statistics was t-1.14, use a 0.05, compute the p-value and decide if Ho b rejected or not...
A two-sample t test of the hypothesis HO: u1-u2=0 versus HA: u1-u2>0 produces a p-value of 0.03. Which of the following must be true? I. A 90 percent confidence interval for the difference in means will contain the value 0. II. A 95 percent confidence interval for the difference in means will contain the value 0. III. A 99 percent confidence interval for the difference in means will contain the value 0. a.) I only b.) III only c.) I...
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