Test Statistic :-
t = - 1.757
Looking for the value t = 1.757 in t table across n - 1 = 15 - 1 = 14 degree of freedom for one tailed test
Value t = 1.757 lies between the values in t table
Respective P values for one tailed is
0.05 < P value of the test < 0.10
Using excel we can calculate exact P value = 0.0504
The one-sample -statistic for a test of Ho: u = 42 versus H1: /i < 42 based on n = 15 observations has the value 1=1...
The one-sample t-statistic for a test of Hou = 42 versus H1:4 < 42 based on n = 15 observations has the value t= -1.343, where Ho and H are the null and alternative hypotheses, respectively. The sample size is denoted by n. Use this t-table to determine which two P-values bracket the P-value of the test. Report your answers in decimal form as listed in the t-table. K P-value of the test <
The one-sample 1-statistic for a test of Hou = 42 versus H: < 42 based on n= 15 observations has the value I = -1.757, where Ho and H are the null and alternative hypotheses, respectively. The sample size is denoted by n. Use this 7-table to determine which two P-values bracket the P-value of the test. Report your answers in decimal form as listed in the i-table. C P KP-value of the test -value of the test < 0
The one-sample t-statistic for a test of Ho: = 42 versus H:# < 42 based on n = 15 observations has the value t = -2.138, where H, and Hare the null and alternative hypotheses, respectively. The sample size is denoted by n.
5. The one-sample t statistic for a test of based on n-10 observations has the value t--2.25. a. What are the degrees of freedom for this statistic? b. What is the P-value for this test?
The one-sample t statistic from a sample of n = 13 observations for the two-sided test of the following hypotheses has the value t 1.49. Hoi 64 H 64 (a) What are the degrees of freedom for t? df = (b) Locate the two critical values t from Table C that bracket t. (Use 3 decimal places.) <t What are the twwo-sided P-values for these two entries? <P-value 1.49 significant at the 10 % level? (d) Is the value t...
please explain Duppose a one-sample t test from a sample of n = 10 observations for the hypotheses Ho = 64 versus HA: +64 has the test statistic t = 3.21. The P-value for this test 15 a) greater than 0.02 b) between 0.0025 and 0.005 c) between 0.005 and 0.01 o uth d) between 0.01 and 0.02 e) not possible to be found for a negative test statistic. a mil
A test is made of Ho: u= 50 versus H1: u50. A sample of size n = 71 is drawn, and =56. The population standard deviation is o = 29. Compute the value of the test statistic z and determine if H is rejected at the a = 0.05 level. A) 0.21, Ho not rejected B) 1.74, Ho rejected D) 1.74, Ho not rejected C) 0.21, Ho rejected The Golden Comet is a hybrid chicken that is prized for its...
The p-value for a test of Ho: p = 0.25 versus H1: p < 0.25 is 0.0625. The correct p-value for a test of Ho: p=0.25 versus H1: p > 0.25 if the same sample data are used is closest to: ca. 0.1250 b.0.0313 K c.0.9375 i d. 0.0625
(15 points) The t statistic for a test of Ho : 4 = 47 Ha: u > 47 based on n = 17 observations has the value t = 1.61. (a) What are the degrees of freedom for this statistic? 16 (b) Using the appropriate table in your formula packet, bound the p-value as closely as possible: <p-value <
In a test of hypotheses Ho: M = 456 versus H1:4< 456, the rejection region is the interval (-00, -1.796], the value of the sample mean computed from a sample of size 12 is x = 453, and the value of the test statistic is t = -2.598. The correct decision and justification are: O Reject Ho because 453 is less than 456 O Reject Ho because -2.598 lies in the rejection region O Do not reject Ho because -2.598...