6. Calculate the entropy change when 2 moles of gaseous water are formed at 100°C and 1 atm from hydrogen and oxygen ga...
9. The enthalpy of decomposition of gaseous water to oxygen and hydrogen at 298 K and 1 atm is 241.75 kJ/mol. Calculate its value at 348 K. The molar heat capacity values (in J/K.mol) are: Cm (H20) 33.56, C.m (O2) 29.12, Cm (H2) 28.82.
Calculate the change in entropy (in J/K) that occurs when a sample containing 2.00 moles of water is heated from 10.00°C to 300.0 °C at 1 atm pressure. Molar Heat Capacity H2O(1) = 75.3 JK' moi? H2O(g) = 36.4 JK' mol Enthalpy of Vaporization at 100 °C = 40.7 kJ mol .-1 -1 Answer:
Calculate the change in entropy (in J/K) that occurs when a sample containing 2.00 moles of water is heated from 80.00 °C to 110.0 °C at 1 atm pressure. Molar Heat Capacity H20(I) = 75.3 JK' molt H20(9) = 36.4 JK' moi Enthalpy of Vaporization at 100 °C = 40.7 kJ moi? -1 Answer:
Calculate the entropy change from burning 41.1 g of solid glucose (C6H1206, molar mass 180.2 g/mol) to produce gaseous carbon dioxide and gaseous water, using the values in the table below. S0/JK mor Substance Glucose(s) O2(g) CO2(g) H2O(g) 209.2 205.15 213.79 188.84 Select one: a. 4.01e4 J/K b. 223 J/K C. -2.67 J/K d. None of the other options e. -482 J/K
Calculate the change in entropy ΔS for 5.2 moles of an ideal gas when its thermodynamic state changes from p1 = 1.50 atm and T1 = 400.0 K to p2 = 3.00 atm and T2 = 600.0 K. The molar heat capacity of the gas at constant volume is CV,m = (7/2) R, and is independent of the temperature.
Gaseous H2O is condensed at 100°C and the liquid water is cooled to 0°C followed by freezing to solid water. What is the molar entropy change of the water? Consider the average specific heat of liquid water is 4.2 J/K g. The heat of vaporization at the boiling point and the heat of fusion at the freezing point at 2258.1 and 333.5 J/g, respectively.
When one mole of gaseous hydrogen peroxide, H2O2, is made from hydrogen and oxygen gases, the enthalpy change is –136 kJ. Which of the following correctly represents the thermochemical equation? i. H2(g) + O2(g) → H2O2(g) + 136 kJ ii. H2(g) + O2(g) + 136 kJ → H2O2(g) iii. H2(g) + O2(g) → H2O2(g) ΔH = –136 kJ iv. H2(g) + O2(g) → H2O2(g) ΔH = +136 kJ A.i only B.ii only C.iii only D.i and iii E.ii and iv
Calculate the change in entropy that occurs when 18.02 g of ice at –17.5°C is placed in 90.08 g of water at 100.0°C in a perfectly insulated vessel. Assume that the molar heat capacities for H2O(s) and H2O(l) are 37.5 J K^-1 mol^-1 and 75.3 J K^-1 mol^-1, respectively, and the molar enthalpy of fusion for ice is 6.01 kJ/mol. Change in entropy = ______J/K
Calculate the entropy change from burning 67.3 g of solid glucose (C6H12O6, molar mass 180.2 g/mol) to produce gaseous carbon dioxide and gaseous water, using the values in the table below. Substance S0 / J K-1 mol-1 Glucose(s) 209.2 O2(g) 205.15 CO2(g) 213.79 H2O(g) 188.84
1. a) Calculate the change in entropy (AS) when one mole of diamond is heated from a temperature of 0 K to 400 K at a constant pressure of 1 bar. The temperature-dependent heat capacity of diamond is C 2.9x10 T J/(mol K), where T is the absolute temperature in K. b) Given that the entropy of diamond is zero at 0 K, calculate its absolute molar entropy (S) at 400 K from the above result.