When one mole of gaseous hydrogen peroxide, H2O2, is made from hydrogen and oxygen gases, the enthalpy change is –136 kJ...
When one mole of gaseous hydrogen peroxide, H2O2, is made from hydrogen and oxygen gases, the enthalpy change is –136 kJ. Which of the following correctly represents the thermochemical equation?
i. H2(g) + O2(g) → H2O2(g) + 136 kJ
ii. H2(g) + O2(g) + 136 kJ → H2O2(g)
iii. H2(g) + O2(g) → H2O2(g) ΔH = –136 kJ
iv. H2(g) + O2(g) → H2O2(g) ΔH = +136 kJ
A.i only B.ii only C.iii only D.i and iii E.ii and iv
Homework Answers
enthalpy change is negative
So,
ΔH would be negative
Also heat must be added in product and not reactant because heat is released
So I and iii are correct
Answer: D
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