Question

A boy of mass 60 kg and a girl of mass 40 kg are together and...

A boy of mass 60 kg and a girl of mass 40 kg are together and at rest on a frozen pond and push each other apart. The girl moves in a negative direction with a speed of 3 m/s. What must be the final momentum of the boy?
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Answer #1

Given:

Mass of boy = 60 kg

Mass of girl M​​​​​​g = 40 kg

Final velocity ( V​​​​​​2g​​​​) of girl in negative direction = 3m/s

Consider the frozen pond to be frictionless

Apply conservation of momentum

Initial momentum of girl and boy = final momentum of girl and boy

initial momentum of girl and boy is zero as they are at rest

= 0 = final momentum of girl + final momentum of boy ( P​​​​​​f)

= 0 = M​​​​​​​​​​g * (V​​​2g ) + P​​​​​f

0 = 40 * (-3) + P​​​​​​f

P​​​​​​f = 40*3

Final momentum of boy = 120 kg- m/s ( direction : positive direction )

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