Given:
Mass of boy = 60 kg
Mass of girl Mg = 40 kg
Final velocity ( V2g) of girl in negative direction = 3m/s
Consider the frozen pond to be frictionless
Apply conservation of momentum
Initial momentum of girl and boy = final momentum of girl and boy
initial momentum of girl and boy is zero as they are at rest
= 0 = final momentum of girl + final momentum of boy ( Pf)
= 0 = Mg * (V2g ) + Pf
0 = 40 * (-3) + Pf
Pf = 40*3
Final momentum of boy = 120 kg- m/s ( direction : positive direction )
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