Answer
3.00mol
Explanation
A(g) + 3B(g) -------> 2C(g)
Stoichiometrically, 1mole of A reacts with 3moles of B
given moles of A = 2.00mol
given moles of B = 4.50mol
2.00moles of A require 6.00moles of B but available moles of B is 4.50mol
Therefore ,
Limiting reagent is B
stoichiometrically, 3moles of B gives 2moles of C
moles of C obtained by 4.50moles of B = (2/3)×4.50mol = 3mol
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