here,
r1 = 0.3 m
q1 = 9.5 nC = 9.5 * 10^-9 C
the electric feild due to q1 , E1 = - K * q1 /r1^2 i
E1 = - 9 * 10^9 * 9.5 * 10^9 /0.3^2 i N/C
E1 = - 950 i N/C
r2 = 0.1 m
q2 = - 3 nC = - 3 * 10^-9 C
the electric feild due to q2 , E2 = - K * q2 /r2^2 j
E2 = - 9 * 10^9 * 3 * 10^9 /0.1^2 j N/C
E2 = - 2700 j N/C
the vector electric feild on 5 nC , E = E1 + E2
E = - 950 i N/C - 2700 j N/C
b)
q3 = 5 nC = 5 * 10^-9 C
the vector force , F = q3 * E
F = 5 * 10^-9 C * ( - 950 i N/C - 2700 j N/C)
F = (- 4.75 i - 13.5 j) uN
Three point charges are arranged as shown in the figure below. 5.00 nC 0.300 m9 0.100...
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