Question

Show that: olve the differential equation above by integration from T to T2 to obtain an expression would allow you to relate AA at the two temperatures.

Answer 1

The given expression can be shown by following as - By definition A = U-TS 0 and from basic thermodynamic equation A = -sat-pav >> A =-S Putting on equation we get n e A = U + T.(-s) >> A = Uit T. (2) - - u=-ATT (3A/OT) Dividing day - - 2 + 1 - (0) >> - - - + + H/07). -%e* = [('4)+ + Ct). Lam (A4) 7 uz +18 (A/T). & (/) 7 UTO (A/T) 7 L (D). Ja u = CAT) I [-DT) ~) Jv 1 u= a(AT) (1+) Iv. T AIT) I allt). Ju (shown)

. Given ra(A/T) 7 EU Lalit Jv => [ 2007 ], -0 >> -p [ O (APN) 1 - 0 - [ 0 (A+)] = udt - Integrating within T, and T2 – e) => [014]. - ["4752 - AA ( 17 ) = U2 - 1 1 1 > on - head)/(-+) so from the above expression 4 A value can be calwlated between T & T .