Question

Three kinetics questions.

Consider the following reaction and experimental data: X+Y-XY Trial [X] (mol/L) [Y] (mol/L) Rate (molls) 0.180 0.0250 0.0640

Consider the following reaction and experimental data: X + Y - XY Trial [X] (mol/L) [Y](mol/L) Rate (molls-1) 1 0.3 1.8 0.6

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Answer #1

1 Given reaction + Y XY Trial [x] (mol/L) 0.18 0.045 0.045 [Y] mol/L) 0.025 0.025 Rate (MIS) 0.064 0.016 0.075 0.048 let ratenow, putting the value of a and is in ean (1) 0.064 M/S = K[0.19] [0-025M] now, rate at [x]- 1:15M :CY] = 0.6674 rate= k [1.1now, dividing eqh in by epen 0.31MIS K [0.8M] [o.umiy =) 0.077 M/S (0.3 MJ [0:24] y = 2 so rate law is vate = k [A] [B]² putdividing equ (2) by eqn (1) 5.4M/S - K[1.8M]9 (0.3M]b 13 7.8 MIS K[06M]9 [0.3M] b. ...a=1 now, dividing eqh 3rd by eqh (1) 7.

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Three kinetics questions. Consider the following reaction and experimental data: X+Y-XY Trial [X] (mol/L) [Y] (mol/L)...
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