Work set 2 Using the experimental data given in the table, determine the reaction order on...
Work set 1 Using the experimental data given in the table, derive the rate law and determine the value and the units of k for the following chemical reaction: Sucrose glucose + fructose Exp. Run [Sucrose] Rate (mol/L s) 0.10 0.20 0.40 0.015 0.030 0.060
6. (20 pts) The data below were collected for the following reaction at 25 °C: NO2(g) + CO(g) ? NO(g) + CO2(g) [NO2Initial 0.100 M 0.200 M 0.200 M 0.400 M COJinitial 0.100 M 0.100 M 0.200 M 0.100 M Initial rate 0.0021 Ms 0.0082 Ms 0.0083 Ms 0.033 M s a. (8 pts) What is the rate law for this reaction? (in the form Rate k[NOJ'icoj) b. (6 pts) What is the value of K? (Be careful with units...
Use the following data to determine the individual and overall reaction orders. NO(g)+ CO2(g) rate kINO,1"[coj NO2u)+ COE) Experiment Initial Rate(M/S) Initial INO,L(M Initial ICOL (M) 0.0050 0.080 0.0050 0.10 0.40 0.10 0.10 0.10 0.20
23. Given the following experimental data, find the rate law and the rate constant for the reaction: NO (8) + NO2 (g) + O2(g) → N2O(g) Run (NO), M (NO2), M (O2)., M. Initial Rate, Ms? 0.10 M 0.10 M 0.10 M 2.1 x 102 0.20 M 0.10 M 0.10 M 4.2 x 102 - NM + 0.20 M 0.30 M 0.20 M 1.26 x 102 0.10 M 0.10 M 0.20 M 2.1 x 102
Exhibit 13-8 Consider the gas phase reaction and data below to answer the following question(s). NO2 (g)+ CO (R)NO (g)+CO2 (g) Initial Rate M/sec) 0.0050 0.080 NO2], M ICO, M Experiment 1 0.10 0.40 0.10 2 0.10 0.10 0.20 0.0050 4. Refer to Exhibit 13-8. What is the rate law for this reaction? a. Rate- k[NO2l[CO] b. Rate k[NO2][CO]2 c. Rate = k[NO2] [CO] d. Rate k[NO2]Ico2 e. Rate
Experimental data is collected for the reaction shown below, with the following rate law: rate=k[NO2]2. What are the units of the rate constant for the reaction? NO2(g)+CO(g)→NO(g)+CO2(g) Trial123[NO2] (mol/L)0.060.060.09[CO] (mol/L)0.060.090.06Rate(mol L−1s−1)1.5408×10−61.5408×10−63.4668×10−6
(2 points each a-f) The data below were collected for the following reaction: 2 NO2 (g) Cl2 (g) >2 NO2CI (g) Initial rate (M/s) [NO2] (M) [CI2 (M) 0.051 0.200 0.100 0.400 0.100 0.103 0.105 0.400 0.200 0.800 0.400 0.207 a. Calculate the order of the reaction with respect to NO2 (). b. Calculate the order of the reaction with respect to Cl2 (/). Write the Rate Law expression including the correct order of reaction for each reactant. c. d....
question 6, please! 5. Consider the following gas phase reaction and data to answer the next five questions. NO2 (g)CO (g) NO (g) +CO2 (g) Experiment [NO2, M [CO], MInitial Rate (M/sec) 0.10 0.10 0.0050 0.40 0.10 0.080 2 3 0.100.200.0050 What is the rate law for this reaction? A) Rate KNO22 B) Rate KINO2lICO]2 C) Rate = 서NO2][CO] D) Rate KNO21Co12 E) Rate KNO212co] 6. What is the numerical value for the rate constant, k of the reaction above?...
B1. The following experimental data were obtained for the following reaction at 1000 K: 2 NO(g) + O2(g) 2 NO2(g) NOI (mol L OJ (mol L- Inital rate of reaction (mol L-'s - 0.0100 0.0200 0.0300 0.0200 0.0500 0.0200 3.02 x 10-5 3.02 x 10-4 2.72 x 10-4 (a) Determine the order of the reaction for each reactant (b) Determine the overall order of the reaction. Answer: (c) Calculate the rate constant at this temperature.
To understand how elementary steps make up a mechanism and how the rate law for an elementary step can be determined. Very often, a reaction does not tell us the whole story. For instance, the reaction NO2(g)+CO(g)→NO(g)+CO2(g)NO2(g)+CO(g)→NO(g)+CO2(g) does not involve a collision between an NO2NO2 molecule and a COCO molecule. Based on experimental data at moderate temperatures, this reaction is thought to occur in the following two steps: NO2(g)+NO2(g)→NO3(g)+NO(g)NO2(g)+NO2(g)→NO3(g)+NO(g) NO3(g)+CO(g)→CO2(g)+NO2(g)NO3(g)+CO(g)→CO2(g)+NO2(g) Each individual step is called an elementary step. Together, these...