6. (20 pts) The data below were collected for the following reaction at 25 °C: NO2(g)...
(2 points each a-f) The data below were collected for the following reaction: 2 NO2 (g) Cl2 (g) >2 NO2CI (g) Initial rate (M/s) [NO2] (M) [CI2 (M) 0.051 0.200 0.100 0.400 0.100 0.103 0.105 0.400 0.200 0.800 0.400 0.207 a. Calculate the order of the reaction with respect to NO2 (). b. Calculate the order of the reaction with respect to Cl2 (/). Write the Rate Law expression including the correct order of reaction for each reactant. c. d....
Work set 2 Using the experimental data given in the table, determine the reaction order on each reactant and compute the overall rate of the following chemical reaction: NO2CI(g)+3 CO (g) ->NO (g) + 3 CO2(g) Rate (mol/L-s) Exp. Run [NO2](M) [COJ(M) 0.10 0.0021 1 0.10 0.0082 0.20 0.10 3 0.0083 0.033 0.20 0.20 4 0.10 0.40
8) The rate law for the following reaction N2O(g) + NO2(g) → 3NO(g) is Rate = k [N2O][NO2]2. Fill in the blank in the table below. Experiment [N2O], M [NO2], M Initial Rate, MS-1 1 0.100 0.100 2.0x10-3 2 0.300 0.100 6.0x10-3 3 0.100 0.200 ? a) 2.0x10−3 Ms−1 b) 4.0x10−3 Ms−1 c) 8.0x10−3 Ms−1 d) 6.0x10-3 Ms-1 e) 1.0x10−2 Ms−1
Experimental data is collected for the reaction shown below, with the following rate law: rate=k[NO2]2. What are the units of the rate constant for the reaction? NO2(g)+CO(g)→NO(g)+CO2(g) Trial123[NO2] (mol/L)0.060.060.09[CO] (mol/L)0.060.090.06Rate(mol L−1s−1)1.5408×10−61.5408×10−63.4668×10−6
For the reaction 3A(g) + 2B(g) → 2C(g) + 2D(g) the following data was collected at constant temperature. Determine the correct rate law for this reaction and value of rate constant. Trial Initial [A] Initial [B] Initial Rate (mol/L) (mol/L) (mol/(L• min)) 1 0.200 0.200 1.20 × 10–1 2 0.200 0.100 6.00 × 10–2 3 0.100 0.200 3.00 × 10–2 Predict the rate of reaction for Trial #4 using the correct rate law and rate constant. 4 0.300 0.200 ?????????
For the reaction 3A(g) + 2B(g) → 2C(g) + 2D(g) the following data was collected at constant temperature. Determine the correct rate law for this reaction. Trial Initial [A]mol/L Initial[B]mol/L Initial Rate 1 0.200 0.100 6.00*10^-2 2 0.100 0.100 1.50 *10^-2 3 0.200 0.200 1.20*10^-1 4 0.300 0.200 ???????? Predict the rate of the reaction for Trial #4
You have the following reaction: NO2 (g) + CO (g) ⟶ NO (g) + CO2 (g) The rate constant (k) at 701 K is 2.57 M-1s-1. If the activation energy is 150 kJ/mol, what is k at 895 K? R = 8.314 J/(mol*K) A) 680 M-1s-1 B) 443 M-1s-1 C) 2.58 M-1s-1 D) 0.950 M-1s-1 E) 6.52 M-1s-1
we - Google Given the following data, determine the rate law for the following reaction 2A+B+2C - products Experiment 2 [A] 0.273 0.819 0.273 0.273 [B] [C] Rate (M/s) 0.763 0.400 3.0 0.763 0.400 9.0 1.526 0.400 12.0 0.763 0.800 4 6.0 Rate = k[A][B][C] Rate = k[A][B][C] Rate = K[A] [B]*C]2 Rate = K[A]2[B] [CH Rate = k[A] [B][C] Question 16 5 pts SOCl2 gas dissociates into SO2 and Cly via the following reaction: SOCI2(e) + SO2(g) + Cl2(8)...
The reaction NO2(g) + CO(g) CO2(g) + NO(g) has a rate constant of 2.57 M−1∙s−1 at 701 K and 567 M−1∙s−1 at 895 K. Find the activation energy in kJ/mol
Applicati 6. For a generic reaction A + B C, the following data are obtained Experiment Initial /AL. M Initial (e). M Initial rate (M/s 0.100 M 0.100 M 0.100 M 0.200 M 16.0 x 10 16.0 x 10 0200 M 0,100M 64.0 x10 64.0 x 10 0.100 M a. (5 pts) Based on the data, what is the rate law for the reaction? b. (5 pts) using experiment #2's data, solve for k. (5 pts) For experiment #2, after...