Homework Answers
when concentration of sucrose doublled from 0.10 M to 0.20 M rate also doublled from 0.015 to 0.030
so with respect to sucrose reaction is first order .
rate law as follows
rate = K [sucrose]
now
K = rate / [sucrose ]
K = 0.015 / 0.10
K = 0.15 s-1
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Work set 1 Using the experimental data given in the table, derive the rate law and...
Work set 2 Using the experimental data given in the table, determine the reaction order on...
Work set 2 Using the experimental data given in the table, determine the reaction order on each reactant and compute the overall rate of the following chemical reaction: NO2CI(g)+3 CO (g) ->NO (g) + 3 CO2(g) Rate (mol/L-s) Exp. Run [NO2](M) [COJ(M) 0.10 0.0021 1 0.10 0.0082 0.20 0.10 3 0.0083 0.033 0.20 0.20 4 0.10 0.40
23. Given the following experimental data, find the rate law and the rate constant for the...
23. Given the following experimental data, find the rate law and the rate constant for the reaction: NO (8) + NO2 (g) + O2(g) → N2O(g) Run (NO), M (NO2), M (O2)., M. Initial Rate, Ms? 0.10 M 0.10 M 0.10 M 2.1 x 102 0.20 M 0.10 M 0.10 M 4.2 x 102 - NM + 0.20 M 0.30 M 0.20 M 1.26 x 102 0.10 M 0.10 M 0.20 M 2.1 x 102
For the reaction: 2N205 (g) →4NO2(g) +O2(g) The experimental data for this reaction is t:0.0 s...
For the reaction: 2N205 (g) →4NO2(g) +O2(g) The experimental data for this reaction is t:0.0 s [N205] = 0.80 M NO2):0.0 M [O21:00 M t; 20.0 s[N205]=0.20 M INO 1.2M [O2-0.30 M was the average rate of formation of NO2 and O2 during the 20 second time interval? The average rate of formation of NO2 was +0.030 M/s, and the average rate of formation of 02 was +0.030 M's The average rate of formation of NO2 was +0.030 M/s, and...
Experimental data is collected for the reaction shown below, with the following rate law: rate=k[NO2]2. What...
Experimental data is collected for the reaction shown below, with the following rate law: rate=k[NO2]2. What are the units of the rate constant for the reaction? NO2(g)+CO(g)→NO(g)+CO2(g) Trial123[NO2] (mol/L)0.060.060.09[CO] (mol/L)0.060.090.06Rate(mol L−1s−1)1.5408×10−61.5408×10−63.4668×10−6
± Experimental Determination of a Rate Law Part B: Calculate the initial rate for the formation...
± Experimental Determination of a Rate Law Part B: Calculate the initial rate for the formation of C at 25 ∘C, if [A]=0.50M and [B]=0.075M. Express your answer to two significant figures and include the appropriate units. Consider the reaction A+2B⇌C whose rate at 25 ∘C was measured using three different sets of initial concentrations as listed in the following table: Trial [A] (M) [B] (M) Rate (M/s) 1 0.50 0.030 9.0×10−3 2 0.50 0.060 1.8×10−2 3 1.00 0.030 3.6×10−2
#1 when table sugar (sucrose), C12H22O11(s) is digested, it is broken down by reacting with water...
#1 when table sugar (sucrose), C12H22O11(s) is digested, it is broken down by reacting with water to produce two simple sugars, glucose and fructose, each with the formula C6H12O6(s). C12H22O11(s) + H2O(l) -----> C6H12O6(s) + C6H12O6(s) An experiment was performed, and the following data were obtained ;( 4marks) Run initial (sucrose) (mol/L) Rate (mol/(Ls)) 1 0.050 3.09x10^-5 2 0.100 6.17x10^-5 3 0.250 1.50x10^-4 #2 For the reaction A + B +2C --> ABC2, the following data were obtained: run (a)...
11 Review LUISlaills Peruuic Table Consider the reaction A + 2B =C Part A whose rate...
11 Review LUISlaills Peruuic Table Consider the reaction A + 2B =C Part A whose rate at 25°C was measured using three different sets of initial concentrations as listed in the following table: What is the rate law for this reaction? Express the rate law symbolically in terms of k, [A], and [B]. View Available Hint(s) [A] | B | Rate ""|(M) (M) (M/s) 0.10 0.030 3.6x10-4 2 0.10 0.060 | 7.2x10-4 3 0.20 0.030 1.4x10-3 Hint 1. How to...
Homework 8-3_1 Reaction Rate Orders, Temp Effects Reaction Rates and Rate Orders The following initial rate...
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Determine the rate law and the value of k for the following reaction using the data...
Determine the rate law and the value of k for the following reaction using the data provided. 2 NO(g) + Br2(g) → 2 NOBr(g) [NO]i (M) [Br2]i (M) Initial Rate (Ms-1) 0.030 0.0055 1.81 x 10-2 0.030 0.0110 3.62 x 10-2 0.060 0.0055 7.25 x 10-2 please show step by step.
2. The following set of data was obtained by the method of initial rates for the...
2. The following set of data was obtained by the method of initial rates for the reaction: BrO3- + 6H* + 5B Experiment [Br03 M 0.10 2 0.20 3 0.20 4 0.10 3Br2 + 3H2O [H]M [Br] M 0.10 0.10 0.10 0.10 0.10 0.15 0.25 0.10 Rate [mol/(L )] 8.0 x 10+ 1.6 x 10-3 2.4 x 10- 5.0 x 10-2 What is the rate law for the reaction? Show all work to receive credit. (5 points)
Work set 2 Using the experimental data given in the table, determine the reaction order on each reactant and compute the overall rate of the following chemical reaction: NO2CI(g)+3 CO (g) ->NO (g) + 3 CO2(g) Rate (mol/L-s) Exp. Run [NO2](M) [COJ(M) 0.10 0.0021 1 0.10 0.0082 0.20 0.10 3 0.0083 0.033 0.20 0.20 4 0.10 0.40
23. Given the following experimental data, find the rate law and the rate constant for the reaction: NO (8) + NO2 (g) + O2(g) → N2O(g) Run (NO), M (NO2), M (O2)., M. Initial Rate, Ms? 0.10 M 0.10 M 0.10 M 2.1 x 102 0.20 M 0.10 M 0.10 M 4.2 x 102 - NM + 0.20 M 0.30 M 0.20 M 1.26 x 102 0.10 M 0.10 M 0.20 M 2.1 x 102
For the reaction: 2N205 (g) →4NO2(g) +O2(g) The experimental data for this reaction is t:0.0 s [N205] = 0.80 M NO2):0.0 M [O21:00 M t; 20.0 s[N205]=0.20 M INO 1.2M [O2-0.30 M was the average rate of formation of NO2 and O2 during the 20 second time interval? The average rate of formation of NO2 was +0.030 M/s, and the average rate of formation of 02 was +0.030 M's The average rate of formation of NO2 was +0.030 M/s, and...
11 Review LUISlaills Peruuic Table Consider the reaction A + 2B =C Part A whose rate at 25°C was measured using three different sets of initial concentrations as listed in the following table: What is the rate law for this reaction? Express the rate law symbolically in terms of k, [A], and [B]. View Available Hint(s) [A] | B | Rate ""|(M) (M) (M/s) 0.10 0.030 3.6x10-4 2 0.10 0.060 | 7.2x10-4 3 0.20 0.030 1.4x10-3 Hint 1. How to...
Homework 8-3_1 Reaction Rate Orders, Temp Effects Reaction Rates and Rate Orders The following initial rate data was collected for the reaction: HI(g) + CHşl(g) à CH.(g) +1-(9) Experiment (HI) (CHI) Initial Rate 0.015 M0.900 M 4.01 x 10M's 0.030 M0.900 M 8.04 x 10'Ms 0.030 M0.450 M 3.99 x 10 m/s 1. What is the rate law for this reaction? a. Rate =k [HI] [CHI] b. Rate = k [HI] [C,H,I] c. Rate = k [HI] (C,H,I] d. Rate...
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