Exercise 4 Leta(c)-c1/2 and let c2 > cı > 0 be given. Let: π1c1+12c2. where π2...
Exercise 4 Leta(c) = c1/2 and let c! > cı > 0 be given. Letc= π1c1+12c2, where 1- () Sketch the function u and indicate in your sketch the points (ci,u), u()), and (c,u()). (ii) Draw the line that connects the two points (q, u(c) and (c2,น(e)) and represent that line algebraically, [Hint Find the slope and intercept in terms of the two points, (c,a(c) and e, u()).1 (i) Use that algebraic result to show that the point (č, mu(G)+...
please do not copy the answer of another question!! Exercise 4 Letu (c-c1/ 2 and let c. > c.> 0 be given. Leti-T1qt12 C2: where π2-1-n. (i) Sketch the function u and indicate in your sketch the points (ci, u(c)), ,u()), and (cr, u (a)). (i) Draw the line that connects the two points (c1, u(c)) and (c, u(c2)) and represent that line algebraically. [Hint: Find the slope and intercept in terms of the two points. (a,u(c)) and (q, u(c))...
2. Consider the following linear model where C1 has not yet been defined. Max s.t. z = C1x1 + x2 X1 + x2 = 6 X1 + 2.5x2 < 10 X1 > 0, x2 > 0 Use the graphical approach that we covered to find the optimal solution, x*=(x1, xỉ) for all values of -00 < ci so. Hint: First draw the feasible region and notice that there are only a few corner points that can be the optimal solution....
→ (1 point) Let Vf-6xe-r sin(5y) +1 5e* cos(Sy) j. Find the change inf between (0,0) and (1, n/2) in two ways. (a) First, find the change by computing the line integral c Vf di, where C is a curve connecting (0,0) and (1, π/2) The simplest curve is the line segment joining these points. Parameterize it: with 0 t 1, K) = dt Note that this isn't a very pleasant integral to evaluate by hand (though we could easily...
(1 point) Let Vf =-8xe-r sin(5y) 20e-x. cos(Sy) j. Find the change inf between (0,0) and (1, π/2) in two ways vf . dr, where C is a curve connecting (0,0) and (1.d2). (a) First, find the change by computing the line integral The simplest curve is the line segment joining these points. Parameterize it: with 03t s 1, r(t)- so that Icvf . di- Note that this isn't a very pleasant integral to evaluate by hand (though we could...