Solution :
Given that,
Degrees of freedom = df = 5
a) At 95% confidence level
= 1 - 95%
=1 - 0.95 =0.01
/2
= 0.025
t/2,df
= t0.025,5 = 2.571
b) Degrees of freedom = df = 20
At 95% confidence level
= 1 - 95%
=1 - 0.95 =0.01
/2
= 0.025
t/2,df
= t0.025,20 = 2.086
c) Degrees of freedom = df = 20
At 99% confidence level
= 1 - 99%
=1 - 0.99 =0.01
/2
= 0.005
t/2,df
= t0.005,20 = 2.845
d) n = 5
Degrees of freedom = df = n - 1 = 5 - 1 = 4
At 99% confidence level
= 1 - 99%
=1 - 0.99 =0.01
/2
= 0.005
t/2,df
= t0.005,4 = 4.604
d) Degrees of freedom = df = 23
At 97.5% confidence level
= 1 - 97.5%
=1 - 0.975 =0.025
/2
= 0.0125
t/2,df
= t0.0125,23 = 2.398
f) n = 36
Degrees of freedom = df = n - 1 = 36 - 1 = 35
At 99% confidence level
= 1 - 99%
=1 - 0.99 =0.01
/2
= 0.005
t/2,df
= t0.005,35 = 2.724
Determine the t critical value for a lower or an upper confidence bound in each of...
Determine the t critical value for a lower or an upper confidence bound in each of the following situations. (Round your answers to three decimal places.) (a) Confidence level = 95%, df = 5 2.571 (b) Confidence level = 95%, df = 20 2.086 (c) Confidence level = 99%, df = 20 2.845 x (d) Confidence level = 99%, n = 5 4.604 (e) Confidence level = 97.5%, df = 23 2.398 (f) Confidence level = 99%, n = 36...
Determine the t critical value for a two-sided confidence interval in each of the following situations. (Round your answers to three decimal places.) (a) Confidence level = 95%, df = 10 (b) Confidence level = 95%, df = 15 (c) Confidence level = 99%, df = 15 (d) Confidence level = 99%, n = 5 (e) Confidence level = 98%, df = 22 (f) Confidence level = 99%, n = 38 You may need to use the appropriate table in...
10. -/10 points DevoreStat9 7.E.030 Determine the t critical value for a two-sided confidence interval in each of the following situations. (Round your answers to three decimal places.) (a) Confidence level = 95%, df = 10 (b) Confidence level 95%, dr 15 (c) Confidence level-99%, df 15 d) Confidence level = 99%, n = 10 (e) Confidence level 98%, df-23 (f) Confidence level 99%, n-34
Determine the t critical value for a two-sided confidence interval in each of the following situations. (Round your answers to three decimal places.) (a) Confidence level-95%, df-10 (b) Confidence level-9596, d-15 (c) Confidence level = 9996, df = 15 (d) Confidence level 99%, n-10 (e) Confidence level-98%, af 21 (F) Confidence level 99%, n36
Determine the confidence level for each of the following large-sample one-sided confidence bounds. (Round your answers to the nearest whole number.) (a) Upper bound: 7+ 1.045/n (b) Lower bound: - 1.88s/n (c) Upper bound: X + 0.845/ You may need to use the appropriate table in the Appendix of Tables to answer this question.
Determine the confidence level for each of the following large-sample one-sided confidence bounds. (Round your answers to the nearest whole number.) (a) Upper bound: x + 1.28s/n (b) Lower bound: - 1.888/Vn (c) Upper bound: x + 0.845/vn You may need to use the appropriate table in the Appendix of Tables to answer this question. Need Help? Read It Watch It Talk to a Tutor -110 points V DEVORESTAT9 7.E.503.XP. My Notes Ask Your Teacher V An article gave the...
-/10 POINTS DEVORESTAT9 7.E.015. MY NOTES ASK YOUR TEACHER Determine the confidence level for each of the following large-sample one-sided confidence bounds. (Round your answers to the nearest whole number.) (a) Upper bound: x + 1.04s/n % (b) Lower bound: - 2.33s/n (c) Upper bound: x + 0.52s/ You may need to use the appropriate table in the Appendix of Tables to answer this question. Need Help? Read It Watch It Talk to a Tutor -/10 POINTS DEVORESTAT9 7.E.503.XP. MY...
3. 16.66 points DevoreStat9 7.E.015. My Notes Ask Your Determine the confidence level for each of the following large-sample one-sided confidence bounds. (Round your answers to the nearest whole number.) (a) Upper bound: x 1.04s/Vn (b) Lower bound: x - 1.88s/n e) Upper bound: x + 0.52s/V/n You may need to use the appropriate table in the Appendix of Tables to answer this question. Need Help? Read It Talk to a Tutor
and i need help finding the upper bound confidence interval as well Construct a confidence interval of the population proportion at the given level of confidence. x = 120, n = 1200, 95% confidence Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). The lower bound of the confidence interval is LI. (Round to three decimal places as needed.)
Given the data listed in the table, calculate the lower and upper bound for the 95% confidence interval for the mean at X = 6. The regression equation is given by y^ = b0 + b1x. Regression Statistics Statistic Value b0 8.2 b1 0.64 x 4.82 se 1.280 SSX 26.23 SST 45.52 n 40 Give your answers to 2 decimal places. You may find this Student's t distribution table useful. a) Lower bound = b)Upper bound =