Solution :
Given that,
a) confidence level 95% ,df = 10
At 95% confidence level
= 1-0.95% =1-0.95 =0.05
/2
=0.05/ 2= 0.025
t/2,df
= t0.025,10 = 2.228
b)
confidence level 95% ,df = 15
At 95% confidence level
= 1-0.95% =1-0.95 =0.05
/2
=0.05/ 2= 0.025
t/2,df
= t0.025,15 = 2.13
c)
confidence level 99% ,df = 15
At 99% confidence level
= 1-0.99% =1-0.99 =0.01
/2
=0.01/ 2= 0.005
t/2,df
= t0.005,15 = 2.947
d)
confidence level 99% ,n = 10
df = n-1 =9
At 99% confidence level
= 1-0.99% =1-0.99 =0.01
/2
=0.01/ 2= 0.005
t/2,df
= t0.005,10 = 3.25
e)
confidence level 98% ,df =21
At 98% confidence level
= 1-0.98% =1-0.98 =0.02
/2
=0.02/ 2= 0.01
t/2,df
= t0.01,21 = 2.518
f)
confidence level 99% ,n = 36
df = 36-1 =35
At 99% confidence level
= 1-0.99% =1-0.99 =0.01
/2
=0.01/ 2= 0.005
t/2,df
= t0.005,35 = 2.724
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