Question

the 5. If 0.60 g of a gas occupies 300 mL at 27 C and 630 mm Hg of pressure, what is the molar mass of the gas? A sample of nitrogen occupies a volume of 250 mL at 27 C and 630 mm Hg pressure. What will be its volume at STP? 6.

Answer 1

mars of gas = 0.60g. Volume = 3oomL = 0.30 L Temperature = 27C = 300k Pressure = 630 mmily = 630 atm (1 mmily = 11 am] PUEART = WORT (: no] m= WRT = 0.6gx 0.082 Lahm k mult x 300k 6304 ahm x 0.34 760 אמץ m = 59.35 g/mol Mence, molar mars of gas = 59.35 g mal 67 Volume of M₂ intially (u) = 250 mL = 0.250L Volume at STP LV2) = ? mitial Temperature (T) = 27 c = 3ook Initial Pressure (P) = 630 mm Mg = 630 ahm 766 Temperature at STP (Tz) = Pressure at STP (P2) = o.l= 273k 1 atm = PVT2 = 630 cm x 0.25 LX 273k 300k x lam = 0.18858ss t = 188.6 mL Mence, 188.6ml will be the volume of ₂ at STP.