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A comet orbits the Sun in 4,063 years. What is its average orbital distance from the Sun? Express your answer in AU (enter A

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Т- Чо63 Хrs- - 2т ру . Vom ъъ N r - х1 59X. 3. Кір - Чо 6 3 х 3-15х7 27 с (121x 3.2 Хр Ч. 1 СЗХ 2 ) 5 x 10 2т - 10 1.1 S 2r = 3.804 X Jo m. = 3.804 x 10 m -AU 1.5 X 10 m = 2.5398x16? AU Ž 23 254 A.U. r Tr= 254 AU - 3.18 AU = 3-12x1.5x 10 m, 12 4.- |- 6 5 X6 yn 3.15 x 67 TT 1 = 5.54 years ? T = los days X) o° , 6 8 = 1.94 6 8 r - k l LTE 2100 mm 20 T 12 o 2pp2 M= 672 =- о. $2 36 x) 4 Mplanet = 529.61 Mearth . Тв - ? - Чr 12- т° 43 : (* (*) ? ) - (+) - - сч Твор 20 days ПТ

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