Question

test charge from radius R to radius r. Extra work J): Potential at r (r < R) is: 3. Two Equipotential surfaces are shown in the diagram below. The electric field magnitude in 3 different nei Indicate which of these magnitudes is largest, and which is smallest. s are indicated as Ea, Ea, and Ec EA Smallest field: Ans: Largest field: In a certain region of space, the electric potential is given as V(x, y, z)s Ary-8x2 + Cy, where A, B, and C are positive constants. Find the x-, y-, and z-components of the electric field. 4.

Answer 1

Largest $E_B$ and smallest $E_A$.

For equipotential surfaces the the electric field nearby is determined by the radius of curvature.

$E\propto\frac{1}{r}$

$E_A$ is far from both surfaces that's why it should be smallest.

$\vec{E}=-\vec{\nabla}V$

For

$V=Axy-Bx^2&plus;Cy$

$\vec{E}=-(Ay-2Bx)\hat{\imath}-(Ax&plus;C)\hat{\jmath}$