Question

3 8) - Alter ozonolysis and treatment of the unstable ozonide with CH SCH3, compound A was converted to the compound below. What is the structure of compound A? Compound A A) I B) II C) III D) IV 39) Which of the following is (are) formed by ozonolysis of the following alkyne? 39) Дон Монгол A) Only III and IV C) Only I and II B) Only I and IV D) Only II and III 40) Determine the product of the following reaction. 40) он PCC (excess) OH CH C12

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Q 38– As we know ozone is a powerful oxidant to cleavage alkenes to carbonyl Compounds. In this Reaction carbon - carbon double bond is broken. and Carbon – oxygen double bond forms. In the second step, a reducing agent commonly Zinc metal or dimethyl sulfide decompose the intermediate formed at the end of the ozonolysis reaction. The given product compound A is formed by the Reductive ozonolysis of I. I Oz [He clasice CHAS CH3 o compound A 037 CH3 S CH3 (NOT compound A) 03 SO CH ₃ SCH3 C Not compound A) TV 3 Cla (Hence option A is connect) (NOT compound A)

Que 39- - As we know ozonolysis of alkyne Forms a cyclic intermediate with mechanism. Further carboxylic acid are formed when water is introduced 5 2 103 , 1 + . 2 2.40 3 OH OH O on the bases of option No. – Cis above ozonolysis Cleavage correct. Que 40- As we know Pyridinium chloochromate CPCC) oxidizes alcohols. Primary alcohols to aldehydes se condoy alcohols to Ketones. PCC will not oxidize aldetiydes to Carboxylic acids: " 3 Primary all H - 4 z OH secondry alcohol on the the bases of above D option is connect