Concept:- here we use the field due to a spherical charge distribution at its surface, and properties of dipole in an electric field,
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Monday Homework Problem 3.6 The world's largest Van de Graaff generator produces an electric field of...
The collector sphere, or dome, of a Van de Graaff generator builds a net charge of 4.5 x 10-3 C. Determine the magnitude of the electric field at various locations. Hint: Review the properties of conductors in electrostatic equilibrium and use Gauss's law. Assume a spherically symmetric distribution of charge on the collector sphere. a. Determine the magnitude of the electric field inside of the collector sphere. E = N/C b. Determine the magnitude of the electric field at the...
Tthe Van de Graaff generator and sphere we have been assuming since the start that they are not polarizing each other. This is an approximation. In this question we will start to be able to assess how good this approximation is ? (a) Use the approximation that the Van de Graaff generator and ball are uniformly charged spheres to find the E-field very close to the surface of the Van de Graaff generator, at the point where the +ve x-axis...
PLEASE HELP! The metal sphere of a small Van de Graaff generator illustrated in the following figure has a radius of 20.0 cm. When the electric field at the surface of the sphere reaches 3.0 x io6 V/m, the air breaks down, and the generator discharges. What is the maximum potential the sphere can have before breakdown occurs?
Lightning can be studied with a Van de Graaff generator, which consists of a spherical dome on which charge is continuously deposited by a moving belt. Charge can be added until the electric field at the surface of the dome becomes equal to the dielectric strength of air. Any more charge leaks off in sparks as shown in the figure below. Assume the dome has a diameter of 38.0 cm and is surrounded by dry ar with a "breakdown. electric...
The dome of a Van de Graaff generator receives a charge of 2.6 × 10-4 C Find the strength of the electric field in the following situations Hint: Review properties of conductors in electrostatic equilibrium. Also, use the points on the surface are outside a spherically symmetric charge distribution; the total charge may be considered to be located at the center of the sphere.) (a) inside the dome N/C (b) at the surface of the dome, assuming it has a...
Lightning can be studied with a Van de Graaff generator, which consists of a spherical dome on which charge is continuously deposited by a moving belt. Charge can be added until the electric field at the surface of the dome becomes equal to the dielectric strength of air. Any more charge leaks off in sparks as shown in the figure below. Assume the dome has a diameter of 46.0 cm and is surrounded by dry air with a "breakdown" electric...
Wednesday Homework Problem 2.4 Ilf the magnitude of the electric field of an infinite plane of charge at a point 10.0m from the plane is IE) 100.0g, what is the surface charge density ơ? Select One of the Following: (a) 3.12 x 10-C/m2 (b) 1.77 x 10-3C/m2 (c) 8.85 x 10-10C/m2 (d) 1.77 x 10-C/m2 0
The sphere of a Van de Graaff generator has a charge of +3.28 μC. A small metal sphere nearby has a charge of +219 nC. They are separated 2.00 m. Let us set axes so that the origin is at the centre of the Van de Graaff generator and the small sphere is at 2.00ˆi m. They are far enough apart that we can make the approximation that they are not polarizing each other, so they can be treated as...
"question 2 from pset 2" 4. Place an electric dipole in the electric field you found in problem 9 on PSET 2, such that the dipole moment points along the positive x-axis. In a figure, show the direction of the electric field, the dipole moment and the torque exerted by this field on the dipole. Determine the torque on the dipole due to the external electric field, and the work that the electric field does to rotate the dipole into...
(10%) Problem 3: A research-level Van de Graaff generator has a 2.05 m diameter metal sphere with a charge of 5.1 mC on it. 33% Part a) What is the potential near its surface in MV? Assume the potential is equal to zero far away from the surface. Grade Summary Deductions 8% Potential V- 4.47-I 92% sin0 cotanasin acos atanacotan sinhO cosh0 tanhOcotanh0 78 9 HOME Submissions Attempts remaining:6 (2% per attempt) detailed view 0 END 2% 2% 2% 2%...