a) For question 4, the balanced reaction between NaOH and H2SO4 will be
2 NaOH (aq) + H2SO4 (aq) Na2SO4 (aq) + 2 H2O (l)
b) The qcal will be calculated by formula
qcal = Ccal . T
The T for reaction is given by formula T = (Tfinal - Tinitial)
T = (31.2 - 22.3) = 8.9 oC.
Therefore qcal = 21.0 J / oC * 8.9 oC = 186.9 J = 187 J
Since qsolution = m.c.T
Since mass of solution will be find by formula density = mass / volume.
Mass of solution = 25 + 25 = 50 ml
1.00 g / ml = m / 50 ml
Multiply both side by 50 ml.
Therefore 1.00 g / ml * 50 ml = m
m = 50g
qsolution = 50 g * 4.184 J / g oC * 8.9 oC = 1861.88 J = 1860 J
c) Since q for reaction will be -1861.88 J because heat absorbed by solution will be equal to heat lost by reaction and this heat lost will be negative. Therefore heat of reaction (qreaction) is -1861.88 J or -1860 J.
d) Since Hreaction = (qreaction / number of moles)
To find Hreaction first we need to find moles of acid by using formula molarity = moles / volume in litre.
Volume of H2SO4 = 25 ml * (1L / 1000 ml) = 0.025 L
Therefore rearranging formula of molarity for moles
moles = Molarity * volume in liter. Since M = moles / L. Therefore
moles = 1.00 moles / L * 0.025 L = 0.025 mol H2SO4.
For 0.025 mol we have qreaction -1861.88 J. For finding out for one mole we need to divide this value by 0.025.
Therefore, Hreaction = -1861.88 J / 0.025 mol = -74475.2 J / mol
By using dimensional analysis
-74475.2 J / mol * (1kJ / 1000 J) = -74.4752 kJ / mol.
After rounding off the answer will be -74.5 kJ / mol.
In multiple question we have to solve only one question. If you find any mistake please mention in comment box.
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