Question

Calculate the molar concentration of an NaOH solution that required 15.81 mL to com- pletely neutralize 0.509 g of KHP (Remem

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Answer #1

Question 3

Mass of KHP = 0.509 gm

Molar mass of KHP = 204.22 g/mol

Moles of KHP = 0.509 gm/ 204.22 g/mol = 0.002492 Moles

Moles of NaOH reacted = 0.002492 Moles

VOlume of NaOH = 15.81 ml

Molar concentration of NaOH = 0.002492 x 1000 / 15.81 = 0.1576 M

Question 4

Concentration of NaOH = 0.1750 M

VOlume of NaOH = 25 ml

Moles of NaOH reacted = 0.1750 x 25 /1000 = 0.004375‬ Moles

Moles of KHP reacted =  0.004375‬ Moles

Mass of KHP reacted =   0.004375‬ Moles x 204.22 gm/mol = 0.8935 gm

Question 5

Balanced equation:
2 HCl (aq) + CaCO3 (s) ====> CaCl2 (s) + H2O (l) + CO2 (aq)

Question 6

Mass of solid NaOH required = 250 x 0.1 x 40 /1000 = 1 gm

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