Problem 2.21 Use the approximation that Vavg lm for each time ster You throw a metal...
Use the approximation thVavg Pflm for each time step You throw a metal block of mass 0.16 kg into the air, and it leaves your hand at time t = 0 at location <0, 2, 0> m with velocity <6.5, 3.0, 0> m/s. At this low velocity air resistance is negligible. Using the iterative method shown in Section 2.4 with a time step of 0.05 s, calculate step by step the position and velocity of the block at t =...
Use the approximation that v→avg≈p→f/m for each time step. You throw a metal block of mass 0.34 kg into the air, and it leaves your hand at time t= 0 at location <0, 2, 0> m with velocity <4.5, 3.5, 0> m/s. At this low velocity air resistance is negligible. Using the iterative method shown in Section 2.4 with a time step of 0.05 s, calculate step by step the position and velocity of the block at t= 0.05 s,...
Use the approximation that for each time step. You throw a metal block of mass 0.27 kg into the air, and it leaves your hand at time 0 at location <0, 2, 0> m with velocity <3.5, 4.0, 0> m/s. At this low velocity air resistance is negligible. Using the iterative method shown in Section 2.4 with a time step of 0.05 s, calculate step by step the position and velocity of the block at 0.05 s, 0.10 s, and...
Use the approximation that for each time step. You throw a metal block of mass 0.24 kg into the air, and it leaves your hand at time 0 at location <0, 2, 0> m with velocity <2.5, 5.5, 0> m/s. At this low velocity air resistance is negligible. Using the iterative method shown in Section 2.4 with a time step of 0.05 s, calculate step by step the position and velocity of the block at 0.05 s, 0.10 s, and...
Please be very specific on equations used Use the approximation that Vavg p f/m for each time step You throw a metal block of mass 0.16 kg into the air, and it leaves your hand at time t = 0 at location 0, 2, 0> m with velocity 4.0, 6.0, 0> m/s. At this low velocity air resistance is negligible. Using the iterative method shown in Section 2.4 with a time step of 0.05 s, calculate step by step the...
You throw a metal block of mass 0.22 kg into the air, and it leaves your hand at time t=0 at location < 0, 2, 0 >m with velocity< 2.5, 6.0, 0>m/s.At this low velocity air resistance is negligible. Using the iterative method shown in Section 2.4 with a time step of 0.05 s, calculate step by step the position and velocity of the block at t = 0.05s, t =0.10s, and t=0.15. (Express your answers in vector form.) x(t...
Use the approximation that Vavg lm for each time step A spring with a relaxed length of 25 cm and a stiffness of 20 N/m stands vertically on a table. A block of mass 69 g is attached to the top of the spring. You pull the block upward, stretching the spring until its length is now 29.7 cm, hold the block at rest for a moment, and then release it. Using a time step of 0.1 s, predict the...
Problem 2.43 Your answer is partially correct. Try again. Use the approximation that Vavg -Plm for each time step. A block is attached to the top of a spring that stands vertically on a table. The spring stiffness is 58 N/m, its relaxed length is 31 cm, and the mass of the block is 395 g. The block is oscillating up and down as the spring stretches and compresses. At a particular time you observe that the velocity of the...
Use the approximation that Vavg = p m for each time step. A paddle ball toy consists of a flat wooden paddle and a small rubber ball that are attached to each other by an elastic band (figure). You have a paddle ball toy for which the mass of the ball is 0.011 kg, the stiffness of the elastic band is 0.945 N/m, and the relaxed length of the elastic band is 0.280 m. You are holding the paddle so...
Problem 2.42 (Multistep) Use the approximation that Va for each time step A spring with a relaxed length of 25 cm and a stiffness of 12 N/m stands vertically on a table. A block of mass 67 g is attached to the top of the spring. You pull the block upward, stretching the spring until its length is now 29.1 cm, hold the block at rest for a moment, and then release it. Using a time step of 0.1 s,...