Question

You throw a metal block of mass 0.22 kg into the air, and it leaves your hand at time t=0 at location < 0, 2, 0 >m with velocity< 2.5, 6.0, 0>m/s.At this low velocity air resistance is negligible. Using the iterative method shown in Section 2.4 with a time step of 0.05 s, calculate step by step the position and velocity of the block at t = 0.05s, t =0.10s, and t=0.15.

(Express your answers in vector form.)

x(t = 0.05 s)	=	< , , > m
v(t = 0.05 s)	=	< , , > m/s
x(t = 0.10 s)	=	< , , > m
v(t = 0.10 s)	=	< , , > m/s
x(t = 0.15 s)	=	< , , > m
v(t = 0.15 s)	=	< , , > m/s

Answer 1

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