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hello i need some help with this. please provide details.
1) Which compound gives the following spectra? For the H-NMR assign all signals. Interpret mol peak and base peak in the mas
200 180 160 140 120 100 80 60 40 20 ppm t, 1H d, 2 H d. 2 4.2 H 11 10 9 8 7 6 4 3 2 1 0 5 ppm
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Answer #1

IR analysis

the band at around 3025 cm-1 is due to aromatic CH stretching

the 2850 - 2975 cm-1 is due to aliphatic CH stretching

the band at 1500 cm-1 is due to aromatic C=C stretching

Mass analysis

the molecular ion peak at 200 and M+2 at 202 in equal intensity show the presence of bromine atom

1H NMR analysis

the doublet of a doublet at around 7.5 and 6.5 ppm is due to aromatic proton having a para substituent

the quartet at 4 ppm is due to methylene proton attached to an oxygen

the triplet at around 1.5 ppm is due to methyl proton attached to the methylene group

13C NMR analysis

the four peak between 110 - 160 ppm is due to aromatic carbons

the peak at 60 ppm is due to methylene carbon attached to an oxygen

the peak at around 15 ppm is due to methyl carbon

based on the above analysis the structure of the compound is

Br 1-bromo-4-ethoxybenzene

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