Question

A student titrated 0.180 g of an unknown acid with 0.10 M NaOH solution and the follow data set was obtained: mL of 0.1M NAOH

please ignore question1


Titration Curve 14 12 y 0.2821x +1.9794 R- 0.9328 10 8 6 4 2 0 0 15 30 35 40 Volume of NaOH 25 20 10 5 Hd
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Question 2.

The acid is diprotic.

Explanation: There are two raises, one at pH 9, the other at pH 11.2

Question 3.

The acid is weak.

Explanation: At pH 9 (> 7), the acid reached the first-equivalence point.

Question 4.

The MW of the acid is 69.231 g/mol

Explanation: The moles of acid = The moles of acid at the first-equivalence point = (26/1000) L * 0.1 mol/L = 0.0026 mol

i.e. The molar mass of the acid = 0.18 g/0.0026 mol = 69.231 g/mol

Add a comment
Know the answer?
Add Answer to:
please ignore question1 A student titrated 0.180 g of an unknown acid with 0.10 M NaOH...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT