Question 2.
The acid is diprotic.
Explanation: There are two raises, one at pH 9, the other at pH 11.2
Question 3.
The acid is weak.
Explanation: At pH 9 (> 7), the acid reached the first-equivalence point.
Question 4.
The MW of the acid is 69.231 g/mol
Explanation: The moles of acid = The moles of acid at the first-equivalence point = (26/1000) L * 0.1 mol/L = 0.0026 mol
i.e. The molar mass of the acid = 0.18 g/0.0026 mol = 69.231 g/mol
please ignore question1 A student titrated 0.180 g of an unknown acid with 0.10 M NaOH...
please help me answer questions 2 through 6 thanks PILDI student titrated 0.180 g of an unknown acid with 0.10 M NaOH solution and the data set was obtained: mL of 0.IM NaOH pH mL of 0.1M NaOH pH 2.20 20 3.25 22 28 4.00 4.25 4.50 4.81 5.25 5.55 5.75 6.10 6.32 6.70 7.00 9.00 11.20 11.70 12.00 12.22 12.40 12.60 30 32 14 16 36 38 1. Prepare a titration curve using Microsoft Excel. See Appendix C for...
6. A student titrated 50.0 mL of the 0.10 M unknown diprotic H2A with 0. 10 M NAOH. After 25.0 mL of NaOH was added, the pH of the resulting solution was 6.70. After 50.0 mL of NaOH was added, the pH of the solution was 8.00. What are the values of Ka1 and Ka2? 6. A student titrated 50.0 mL of the 0.10 M unknown diprotic H2A with 0. 10 M NAOH. After 25.0 mL of NaOH was added,...
In a titration, 25 mL of 0.10 M weak diprotic acid solution was titrated by 0.10 M sodium hydroxide, NaOH, and produced a titration curve listed below. (20 points total) 14,0 3. 12.0 10.0 8.0 pH 6.0 4.0 2.0 10.0 5.0 20.0 30.0 15.0 25.0 Volume of 0.100 M NaOH, mL The acid used in above titration is a weak diprotic acid. Briefly explain how you know it's diprotic from looking at the titration curve and how you know a...
4. A weak acid was titrated with 0.1M NaOH, and the titration curve is shown, 14 12 10 pH of solution 0.600... 4 2 0 2 6 10 12 14 16 18 mL of Base added a. Is this a monoprotic or diprotic acid? b. Estimate the values of the pka(s) for this acid.
4. A weak acid was titrated with 0.1M NaOH, and the titration curve is shown, 14 12 10 8 pH of solution G ... 4 4 6 8 10 14 02 mL of Base added a. Is this a monoprotic or diprotic acid? - has two scemps b. Estimate the values of the pKa(s) for this acid. diprotic moto 32 botol
An unknown acid is titrated with NaOH to obtain the following titration curve. 14 12 LO 8 pH 6 4 2 100 25 50 75 Volume of NaOH (ML) What is the approximate pK, of the unknown acid? 8 12 6
DETERMINATION OF MOLECULAR WEIGHT OF AN UNKNOWN DIPROTIC ACID Use Data Set to answer the following questions 1. Using the data, sketch a titration curve for the titration of the acid with 0.1 M NaOH pH 0 volume of NaOH added 2. Using the first equivalence point, determine the molecular weight of the acid. Use the sequence of steps employed in the in-class exercise. Homework Molecular Weight of an Unknown Diprotic Acid 3. Using the second equivalence point, determine the...
only need answers for 9,10,11 .1016 M NaOH 9. Calculate the molar mass of the unknown diprotic acid. (Must show calculations) ( mol NaOH mol acid L NaOH L NaOH mol NaOH) = mol acid g acid mol acid) = molar mass acid 10. What is the identity or name of the unknown acid 2? 2. 11. Why do we NOT need to measure the pH and create a titration curve (mL of NaOH added versus pH) to determine the...
40.0 ml of an acetic acid of unknown concentration is titrated with 0.100 M NaOH. After 20.0 mL of the base solution has been added, the pH in the titration flask is 5.10. What was the concentration of the original acetic acid solution? [Ka(CH3COOH) = 1.8 × 10–5]
A 0.5220 −g sample of an unknown monoprotic acid was titrated with 9.94×10−2 M NaOH. The equivalence point of the titration occurs at 23.86 mL . Determine the molar mass of the unknown acid.