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A single slit diffraction pattern shown above. The light used to make the pattern has a...

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A single slit diffraction pattern shown above. The light used to make the pattern has a wavelength of 511 nm and the screen is 2.2 m from the slit. If the slit has a width 4 mm, what is the width w of the central maximum in cm?

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Answer #1

We know that, Width of central maximum = 2*lambda*D/a where D is screen distance, a is slit width

= 2*511e-9*2.2/4e-3

= 0.000562 m

= 0.0562 cm answer

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