A single slit diffraction pattern shown above. The light used to make the pattern has a wavelength of 521 nm and the screen is 1.8 m from the slit. If the slit has a width 4 mm, what is the width w of the central maximum in cm?
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Please help solve this with work shown! Thanks!
Here,
let the width of the central maximum is w
d = 4 mm = 0.004 m
screen distance ,D = 1.8 m
wavelength = 521 nm
for the width of central maximum
width of central maximum = 2 * wavelength*D/d
width of central maximum = 2 * 521 *10^-9 * 1.8/0.004
width of central maximum = 4.69 *10^-4 m
the width of central maximum is 4.69 *10-4 m
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