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A 42.1 g piece of metal was heated to 95.4°C and then dropped into a beaker containing 42.0 g of water at 23.00°C. When the w
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Emetal = q water Amount of heat released by metal = Amount of heat gained by water = mSAT 42.1 x 85.1-33-lô xs = +2+0x(32-fb-

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