Question 22 (3 points) A 42.1 g piece of metal was heated to 95.4°C and then...

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Answer 1

Answer #1

Heat lost by metal = heat gained by water

i.e. 42.1 g * specific heat of metal * (95.4 - 32.1) K = 42 g * 4.184 J/g.K * (32.1 - 23) ^oC

i.e. The specific heat of the metal = 0.6 J/g.K

Answer 2

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