Assume that a procedure yields a binomial distribution with a trial repeated n = 18 n=18 times. Use either the binomial probability formula (or a technology like Excel or StatDisk) to find the probability of k = 2 k=2 successes given the probability p = 0.29 p=0.29 of success on a single trial. (Report answer accurate to 4 decimal places.) P ( X = k ) = P(X=k)=
* trying to do this in Exel so far all I have is N=18 P=0.29 K=2 Trying to get exel to compute I'm stuck on the last step I have entered =Binomdist(18,0,29,2) but when I press enter It says I have entered too few arguments for this function.
=BINOMDIST(2,18,0.29,FALSE)= 0.053656
Input FALSE because we are looking for probability
for a point.
Assume that a procedure yields a binomial distribution with a trial repeated n = 18 n=18...
Assume that a procedure yields a binomial distribution with a trial repeated n = 18 times. Use either the binomial probability formula (or a technology like Excel or StatDisk) to find the probability of k = 0 successes given the probability p = 0.36 of success on a single trial.
Assume that a procedure yields a binomial distribution with a trial repeated n = 14 n = 14 times. Use either the binomial probability formula (or a technology like Excel or StatDisk) to find the probability of k = 14 k = 14 successes given the probability p = p = 23/30 of success on a single trial. (Report answer accurate to 4 decimal places.) P ( X = k ) =
Assume that a procedure yields a binomial distribution with a trial repeated n = 8 times. Use either the binomial probability formula (or technology) to find the probability of k = 5 successes given the probability p = 0.31 of success on a single trial. (Report answer accurate to 4 decimal places.) P(X = k) = Submit Question Question 8 Assume that a procedure yields a binomial distribution with a trial repeated n = 15 times. Use either the binomial...
Assume that a procedure yields a binomial distribution with a trial repeated n = 9 times. Use either the binomial probability formula (or technology) to find the probability of k = 6 successes given the probability p = 0.53 of success on a single trial. (Report answer accurate to 4 decimal places.) P(X = k) = C
Assume that a procedure yields a binomial distribution with a trial repeated n = 5 times. Use some form of technology like Excel or StatDisk to find the probability distribution given the probability p = 0.413 of success on a single trial. (Report answers accurate to 4 decimal places.) k P(X = k) 0 1 N 3 4 5 Question Help: Video Post to forum Submit Question
please help with both ***Assume that a procedure yields a binomial distribution with a trial repeated n = 16 times. Find the probability of X > 3 successes given the probability p = 0.26 of success on a single trial. (Report answer accurate to 3 decimal places.) ***Assume that a procedure yields a binomial distribution with a trial repeated n=20n=20 times. Find the probability of x≥11x≥11 successes given the probability p=0.6p=0.6 of success on a single trial. (Report answer accurate...
Assume that a procedure yields a binomial distribution with a trial repeated n=17n=17 times. Use the binomial probability formula to find the probability of k=3k=3 successes given the probability p=p=1/4 of success on a single trial. (Report answer accurate to 4 decimal places.) P(X=3)=
1) Assume that a procedure yields a binomial distribution with a trial repeated n=5n=5 times. Use some form of technology like Excel or StatDisk to find the probability distribution given the probability p=0.444p=0.444 of success on a single trial. (Report answers accurate to 4 decimal places.) k P(X = k) 0 1 2 3 4 5
Assume that a procedure yields a binomial distribution with a trial repeated n times. Use binomial probability formula to the probability of x successes given the probability p of success on a single trial. n=14, x=12, p=0.5
Assume that a procedure yields a binomial distribution with a trial repeated n=5 times. Use some form of technology like Excel or StatDisk to find the probability distribution given the probability p=0.808 of success on a single trial. k P(X = k) 0 1 2 3 4 5