Question

Assume that a procedure yields a binomial distribution with a trial repeated n = 18 n=18...

Assume that a procedure yields a binomial distribution with a trial repeated n = 18 n=18 times. Use either the binomial probability formula (or a technology like Excel or StatDisk) to find the probability of k = 2 k=2 successes given the probability p = 0.29 p=0.29 of success on a single trial. (Report answer accurate to 4 decimal places.) P ( X = k ) = P(X=k)=

* trying to do this in Exel so far all I have is N=18 P=0.29 K=2 Trying to get exel to compute I'm stuck on the last step I have entered =Binomdist(18,0,29,2) but when I press enter It says I have entered too few arguments for this function.

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Answer #1

=BINOMDIST(2,18,0.29,FALSE)= 0.053656


Input FALSE because we are looking for probability for a point.
.

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