Question

1) A 110 mL solution of 0.340 M HCl(aq) is mixed with a solution of 330 mL of 0.150 M HNO3(aq). The solution is then diluted
2) When 38.0 mL of 0.1250 M H2SO4 is added to 100 mL of a solution of Pblu, a precipitate of PbSO4 forms. The PbSO4 is then f
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Answer #1

1)

Mol of H+ from HCl = M(HCl)*V(HCl) in L

= 0.340 M * 0.110 L

= 0.0374 mol

Mol of H+ from HNO3 = M(HNO3)*V(HNO3) in L

= 0.150 M * 0.330 L

= 0.0495 mol

Total mol of H+ = 0.0374 mol + 0.0495 mol

= 0.0869 mol

Answer: 0.0869 mol

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