Q 12)
You can use,
N1 V1 = N2V2
N1= 1.75 M, (initial Molarity)
V1= 37.5 mL ( initial volume)
N2= ? ( final Molarity )
V2 = 125 mL (Final volume)
by putting values we can calculate change in Molarity of HCl solution,
1.75 x 37.5 = N2 x 125
so, N2= (1.75 x 37.5 /125)
=0.525M
so correct answer is option 1)
7) solution -
a) Copper kettle ways 1.06 kg (specific heat of copper is 0.384J/gC
As you know mass of kettle should converted into grams from kg..
1.06 x 1000= 1060 gm
By putting values ,
Heat capacity of kettle in J/C =( 1060 g x 0.384 J/g C)
= 407 J/ C
b) Temperature raised from 21.3 C to 98.3C, so
T = 98.3-21.3 =77 C
We know that amount of heat require =
q = m x C x T
By putting values
q = heat supplied,
q = 1060 g x 0.384 J/ g C x 77 C
= 31342 J
c) specific heat capacity of water = 4.18 J/g C
# Change in temperature = 77 C
# amount of water in = 1.15 liter
# density of water = 0.997 g/mL
We can calculate mass of water by using density =
Mass = density x volume
= 0.997 g/mL x 1.15 L
=1.1465 kg
But we have to convert mass into grams by multiplying 1000,
Mass = 1.146 x 1000
=1146.5 g
By putting values into formula-
q = m X C x T
= 1146.5 g x 4.18 J / g C x 77 C
= 369012 J
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