What is the molarity of a solution made by diluting
(2.1067x10^1) mL of 18.7 M ammonia with enough water to form
(2.07x10^2) mL of solution?
use dilution formula
M1*V1 = M2*V2
1---> is for stock solution
2---> is for diluted solution
Given:
M1 = 18.7 M
V1 = 21.067 mL
V2 = 207 mL
use:
M1*V1 = M2*V2
M2 = (M1*V1)/V2
M2 = (18.7*21.067)/207
M2 = 1.9032 M
Answer: 1.90 M
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