For Part B data is not given
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The standard molar heat of formation of water is -285.8 kJ/mol
since density of water is 1g/mL and mass of 1 mol of water is 18 g
hence volume of 1 mol of water = 18mL (density = mass/ volume)
hence mole of water formed = 76 / 18 = 4.2 mol
hence energy required = 4.2 * (-285.8 kJ/mol) = -1206 kJ/mol
PLEASE LEAVE THE POSITIVE FEEDBACK IF YOU LIKE THE SOLUTION
(b) Why is the magnitude of this value so much larger than the heat of vaporization...
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