Question

2 pts Question 1 A uniform rod is attached to a wall by a hinge at its base. The rod has a mass of 9.0 kg, a length of 2.3 m, is at an angle of 23 above the horizontal, and is held in place by a horizontal cord attached to the other end of the rod and bolted to the wall above the base of the rod. (a) Determine the tension in the cord. 1 pts Question 2 What is the magnitude of the force exerted by the pin in the previous problem? ood overview...pg

Answer 1

A)

Balancing the moments,

Mg (L/2) cos(theta) = T L sin(theta)

Tension, T = 9 x 9.8 x 0.5 x cos(23)/sin(23) = 103.89 N

B)

Horizontal component, H = 103.89 N

Vertical component, V = mg = 9 x 9.8 = 88.2 N

Force, F = sqrt(H^2 + V^2) = 136.28 N

C)

Direction, theta = arctan (V/H) = 40.33°

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