Question

A 30.0 g sample of nitrogen, N2, has a volume of 50.0 L and a pressure of 660. mmHg . What is the temperature of the gas in kelvins? What is the temperature of the gas in degrees Celsius?

Answer 1

T = 493.63 K = 494 K

T = 220 degree celsius

30.0 gm N2 moles of N₂ = 30.0gm 28 gm/mol = 1.0714 mol N₂ & Gas equation PV = nRT P = 660 mmHg = 660 760 T = PV NR v=50.0L n = 1.0714 mol R = 0.0821 atm. l/molix T= (660 affn) x ( 50.0f) (3000 mé) -(0.082 apr.) 28 T = 660 x 50 K 760 30 x 0.0821 T = 493.63 k T = 494K] Tempreture in oc T= 273.15 + °C 493.63 = 273.15 + °C 0 - 493.63 - 273.15 oc - 220.5 T= 220°C