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Question 3 (1 point) Find the pH given that the [OH-] = 0.00093 M. Give your answer to 2 decimal places. Your Answer: Answer
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3 [OH) - 0.00093 poh-dog (oh): - log 10.00093)= 3:03 .PH= 14-pol_ 14-3.03= 10.97 & 0 [H+] - 0.083 pha-log D4+] = -log(0.083)=

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