Question

Combining 0.264 mol Fe2O3 with excess carbon produced 14.9 g Fe.

Fe2O3+3C⟶2Fe+3CO

What is the actual yield of iron in moles?

actual yield:

mol

What is the theoretical yield of iron in moles?

theoretical yield:

mol

What is the percent yield?

percent yield:

%

Answer 1

0.264 mol of Fe₂O3 react with excess carbon produced 14.9 g of te fe o2+36-2Fe +3co no. of moles from mr-mass of I M = molar fe ing mass of fe= 55.85 g/mol D acheal yield of iron in moles n(fe) = m(fe) – M(fe) = 0.267 14.9 = 0.267 mol 55.85 moles actual yield

Page: 2 Theoretical yield of fe in moles make a proportion I mol of 0.266 mol of flzoz fe 03 produce a produces mol of te x mol of Fe x = 0, 264x2 = 0.528 moles Theoretical yield = 0.528 moles actual yield divided 37 percent yield by theoretical is yield % yielde 0.267 & 100%= 0.528 50.56%