Question

What volume, in ml, of 0.43 M NaOH is required to neutralize 10.00 mL of 0.18 M HCI? 0.42 mL O 4.3 mL 4.2 ml 0.025 ml 24 mL

Answer 1

IHL t inault » Inach tito face) (AQ) Face (1 from above reaction, mal batio between HCl and T HCL nach I t NaOH is 1:1 - nHCl =1 InHaL = n Nash l at nNash Equivalence point. ny moles we know, .m=n ma molarity =) in=my] ut volume [HI] UHCl = (n codi] Nash

I since both are strong at Equivalence nautoalization occurs. 2. Crowth] = 0.43m (HC) = 0.18m "Neoh = 0 Uiter = 10.com 1 = v. - NaOH [HE] CHCL (Nould Co.189] [10.oo mi) C0.43m) ~ 4.186 mi wa F 4.. 2mi" .: Ans); 14.2 mil ob noch required.