The balanced equation is
NaOH + HCl -----> NaCl + H2O
Number of moles of NaOH = molarity * volume of solution in L
Number of moles of NaOH = 0.18 * 0.0272 = 0.00490 mole
From the balanced equation we can say that
1 mole of NaOH requires 1 mole of HCl so
0.00490 mole of NaOH will require
= 0.00490 mole of NaOH *(1 mole of HCl / 1 mole of NaOH)
= 0.00490 mole of HCl
molarity of HCl = number of moles of HCl / volume of solution in L
molarity of HCl = 0.00490 / 0.0038 = 1.29 M
Therefore, molarity of HCl = 1.29 M
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