using the equation of linear motion we have
Y = Uyt - 0.5gt^2
-H = 11sin 10 * 3.2 - 0.5*9.8*3.2^2
H = 44.06 m
so the brick is 44.06 m tall
6. 2 points SerCP10 3.P.029 A brick is thrown upward from the top of a bullding...
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