Question

A large sport utility has a mass of 2.7×10³ kg .

Calculate the mass of CO2 emitted into the atmosphere upon accelerating the sport utility vehicle from 0.0 to 67.0 mph . Assume that the required energy comes from the combustion of octane (ΔH∘f=−250.1 kJ/mol) with 30% efficiency. (Hint: Use KE=12mv2 to calculate the kinetic energy required for the acceleration.)

Answer 1

V= 67m 1609.344 m bom malo 29.95168 mis KE = 1 mv2 = 5x2700 x 29.95 KIE. = 12.11 X 102k I - 12 11 KJ. combustion of octane - csnis + 25 o sco toho . - from the standard dora, combustion of octane proceduces = 5074.2 KJ per mole of octane. so, combustim of energy = 5074.2x30 los 1522.3 kJ Then 1211 KJ of eneys will come from 1211 KJ 1522.3 kJ .795 mol

Imol of octane forms & moles of co so .795 mol forms 8 moles cox @ 795 moloctane Imo! octane a 20roo = 6.3 645 mol - Molar mass of col = 44.01 g/mol mass of 44.olx 6- 3645 - 280.ls = 280.10 280.0 37