Question

2. Draw all possible isomers of the following compound and assign all of the hydrogen atoms on each carbon atopm (except for

in question 3, are they asking for the stereoisomers ? which would be six possible stereoisomers ? If so then no need to answer question 3. Thanks.

sorry, i meant question 2.
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Ans: No . Of stereo isomers = 2n (n= no. of chiral centres). Here molecule is having three chiral centres. Therefore possible stereo isomers = 23 = 8.

Add a comment
Know the answer?
Add Answer to:
in question 3, are they asking for the stereoisomers ? which would be six possible stereoisomers...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Which of the following statements is true regarding 13C-NMR How many stereoisomers are possible for 1-bromo-6-methyl-4-heptene-2-ol?...

    Which of the following statements is true regarding 13C-NMR How many stereoisomers are possible for 1-bromo-6-methyl-4-heptene-2-ol? Which of the following statements is true regarding symmetrical compounds in NMR experiments? Which of the following statements is true regarding C-NMR a. Carbon-13 is more sensitive than hydrogen NMR b. Carbon-13 resonances appear over a broader range than H-NMR c. Carbon-13 does not couple do adjacent carbons d. Carbon-13 nuclei cannot couple with Hydrogen nuclei How many stereoisomers are possible for 1-bromo-6-methyl-4-heptene-2-ol? a....

  • 3. Cyclic compounds The presence of the ring in all but very large ring cyclic molecules...

    3. Cyclic compounds The presence of the ring in all but very large ring cyclic molecules prevents full rotation of the ring atoms. For this reason, stereoisomerism may also occur in cyclic molecules. a) Prepare a model of cyclohexane, CH12. Draw the condensed formula b) Build a model of methylcyclohexane (C;H2a) by replacing one of the hydrogens of cyclohexane with a methyl group. Draw the skeletal formula for methylcyclohexane. c) How many different isomers exist for methylcyclohexane (C-Ha)? d) Start...

  • 3. Cyclic compounds The presence of the ring in all but very large ring cyclic molecules...

    3. Cyclic compounds The presence of the ring in all but very large ring cyclic molecules prevents full rotation of the ring atoms. For this reason, stereoisomerism may also occur in cyclic molecules. a) Prepare a model of cyclohexane, C6H12. Draw the condensed formula. b) Build a model of methylcyclohexane (C7H14) by replacing one of the hydrogens of cyclohexane with a methyl group. Draw the skeletal formula for methylcyclohexane. 2 c) How many different isomers exist for methylcyclohexane (CyH34)? d)...

  • 4-chloro-3, 4-dimethylnonan-1-amine Assignment 3: Chiral Carbons and Stereoisomers On a page titled Chiral Carbons...

    4-chloro-3, 4-dimethylnonan-1-amine Assignment 3: Chiral Carbons and Stereoisomers On a page titled Chiral Carbons draw using a chemical drawing program or other computer generated form the expanded structure of your molecule. No hand drawn structures will be accepted. O Determine if your molecule contains any chiral carbons. If there are chiral carbons in your molecule, circle or highlight all of them. If your molecule does not contain any chiral carbons explain why none of the carbons are chiral. One a...

  • A. Enantiomers: Certain substances have the unique property of rotating the plane of plane-polarized light. Such...

    A. Enantiomers: Certain substances have the unique property of rotating the plane of plane-polarized light. Such light rotation is detectable with the aid of a polarimeter. In order for a molecule to be optically active it must be chiral. Chiral objects lack a plane of symmetry and are non-superimposable on their mirror images. A sp?- hybridized carbon atom can fulfill these requirements if all four of its substituents are different. 1. Methane a) Prepare a methane molecule and then substitute...

  • Answer ALL question. Stereochemistry 1) _are isomers which have the same bonding sequence but differ in...

    Answer ALL question. Stereochemistry 1) _are isomers which have the same bonding sequence but differ in the orientation of their atoms in space. A. Stereoisomers B. Alkanes C. Alkenes 2) Which of the following terms best describes the pair of compounds shown: enantiomers, diastereomers, or the same compound? A. The same compound B Diastereomers c Enantiomers 3.) How many asymmetric carbon atoms are present in the following compound? A)0 B) 1 C)2 D)3 E)4 4.) How many asymmetric carbon atoms...

  • LLLL US aliyena. place with CHradio The methyl radical has a nonbonding electron and is able...

    LLLL US aliyena. place with CHradio The methyl radical has a nonbonding electron and is able to form another bond. It can take the place of a hydrogen atom of some alkane and make the molecule larger. Any alkane can be turned into a radical by removing a Bethane hydrogen atom. Table 4.1 gives the names of the radicals derived from the straight-chain alkanes. To name an alkane you need to do three things: 1. Identify the longest chain to...

  • 19-26 thanks! 19-29* PART 3: 2,3-BUTANEDIOL CH-CH(OH)-CH(OH)-CH, mirror images, not superimposable Build as many models of...

    19-26 thanks! 19-29* PART 3: 2,3-BUTANEDIOL CH-CH(OH)-CH(OH)-CH, mirror images, not superimposable Build as many models of 2,3-butanediol as you can. First, attach two carbons with a single bond. To each carbon add one carbon, one hydrogen, and one oxygen. To complete the structure, Ti the remaining hydrogen atoms. Remember, a model is not different if it is completely superimposable on one already constructed! 13. How many stereochemically different models are possible for 2,3-butanediol? 14. What characteristic does one of these...

  • Question 1: Compare the possible ring structures and conformers for fructose and decide which is preferred...

    Question 1: Compare the possible ring structures and conformers for fructose and decide which is preferred (if any). There are four main hemi-ketal rings, one of which is shown below. What factors might influence the preference for 5- or 6-membered rings? Question 2: Make a model of vitamin C. Note the lactone link that forms the ring, rather than the hemi-ketal that is present in fructose. Do you think the presence of sp2 carbons in the ring induce strain? Does...

  • Week 10- Constitutional isomers Constitutional isomers have the same molecular formula, but their atoms are bonded...

    Week 10- Constitutional isomers Constitutional isomers have the same molecular formula, but their atoms are bonded in different orders. These may be further distinguished as chain isomers, which differ only in hydrocarbon chain structure, positional isomers, which differ in the location of a functional group, and functional group isomers which differ in the nature of their functional groups. Typically chain and position isomers show only modest differences in their physical and chemical properties, while functional group isomers differ greatly from...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT