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Given the following equation: N2 (g) + 3 H2 (g) → 2 NH3 (g) How many grams of H2 are required if 44.2 grams of NH3 is produce
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Answer #1

N₂ + 3H2 191 192 Ulls 19). mass of NHS is u4.2 g nolat mass of Hy is 17.039/mol holes of WH₂= mass = 44.29 molas mass 17:03 82.595 meta x. - 3 mol H₂ ... 2 moto#3 B = 3.893 mol H₂ required mass- mol = - - Tmass = molxndas mas. molas mass molto mass o

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