Question

(10%) Problem 6: $sig.gif?tid=2M68-7D-94-42-ABFD-18791$ A fisherman has caught a fish on his pole, and to keep the pole steady he has to apply an upward force of F₂ = 275 N at an angle of 73.5° with respect to the pole (see figure). The length of his pole is 4.3 m, and he is holding it a distance 0.55 m from the end, where he is applying a downward force F₁.

50% Part (a) With how much force, F₁, in newtons, does he have to push straight downward on the end of his pole to keep the pole from moving? You may assume the pole is massless.

50% Part (b) What is the mass of the fish on the end of the pole, in kilograms?

Answer 1

Giren FR = 275 N © = 73.5° LG 4.3 m d = o.sŚ m data J @ Force F1 - make the fish is End the axis of rotation , CL-d) F2 - L(Fl) =0

:. Fi = (L-d) F2 = (4.3 -0.55) 275 4.3 io Fi = 239.82 N ② Mass of the fish o- * make the End with Fl the axis of rotation, d(F2) - L (mg) = 0 m = d F2 - Lxg . - 0.55 X 275 4.3 x 9.8 is m = 3.589 kg - so, mass of fish on End of the pole is, 3.589 kg the