Question
How much does a sleeping bag cost? Let's say you want a sleeping bag that should keep you warm in temperatures from 20°F to 45°F. A random sample of prices ($) for sleeping bags in this temperature range is given below. Assume that the population of x values has an approximately normal distribution.
105 120 105 105 75 70 30 23 100 110
105 95 105 60 110 120 95 90 60 70
(a) Use a calculator with mean and sample standard deviation keys to find the sample mean price x and sample standard deviation s. (Round your answers to two decimal places.)
x = $
s = $

(b) Using the given data as representative of the population of prices of all summer sleeping bags, find a 90% confidence interval for the mean price μ of all summer sleeping bags. (Round your answers to two decimal places.)
lower limit $   
Incorrect: Your answer is incorrect.
upper limit $   
Incorrect: Your answer is incorrect.

Do you want to own your own candy store? Wow! With some interest in running your own business and a decent credit rating, you can probably get a bank loan on startup costs for franchises such as Candy Express, The Fudge Company, Karmel Corn, and Rocky Mountain Chocolate Factory. Startup costs (in thousands of dollars) for a random sample of candy stores are given below. Assume that the population of x values has an approximately normal distribution.
92 178 128 97 75 94 116 100 85
(a) Use a calculator with mean and sample standard deviation keys to find the sample mean startup cost x and sample standard deviation s. (Round your answers to one decimal place.)
x = thousand dollars
s = thousand dollars

(b) Find a 90% confidence interval for the population average startup costs μ for candy store franchises. (Round your answers to one decimal place.)
lower limit thousand dollars
upper limit thousand dollars

How much does a sleeping bag cost? Lets say you want a sleeping bag that should keep you warm in temperatures from 20°F to 4
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Answer #1

from the given data. mean ž - 4x 1753 87.65 η 20 standard deviations & (xox) n-1 [105-18965) tann 60-87.65) 20-1 14678.55 = √a) from mean given data. i = $x 92+128-1128+ ... 85 = 965 = 107.2 Standard deviation & &(2.7) n-) (92-107-2)(178-107-2).. (85

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