Given data,
Magnetic field , B = 0.025 T
Speed = 5.0 x 103 m / s
Angle = 900
a)
A centripetal force acts because of the magnetic force.
So the proton will move in a circular track.
b)
Let us consider,
magnetic force = centripetal force
qVB = mv2/r
r = mv / qB
r = 1.67 x 10-27 x 5000 / 1.6 x 10-19 x 0.25
r = 0.000534 m
= 0.534 mm
Therefore, the radius of the path is 0.534 mm
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